Off-by-one on range boundaries
Wrong move: Loop endpoints miss first/last candidate.
Usually fails on: Fails on minimal arrays and exact-boundary answers.
Fix: Re-derive loops from inclusive/exclusive ranges before coding.
Build confidence with an intuition-first walkthrough focused on core interview patterns fundamentals.
Table: Followers
+-------------+------+ | Column Name | Type | +-------------+------+ | user_id | int | | follower_id | int | +-------------+------+ (user_id, follower_id) is the primary key (combination of columns with unique values) for this table. This table contains the IDs of a user and a follower in a social media app where the follower follows the user.
Write a solution that will, for each user, return the number of followers.
Return the result table ordered by user_id in ascending order.
The result format is in the following example.
Example 1:
Input:
Followers table:
+---------+-------------+
| user_id | follower_id |
+---------+-------------+
| 0 | 1 |
| 1 | 0 |
| 2 | 0 |
| 2 | 1 |
+---------+-------------+
Output:
+---------+----------------+
| user_id | followers_count|
+---------+----------------+
| 0 | 1 |
| 1 | 1 |
| 2 | 2 |
+---------+----------------+
Explanation:
The followers of 0 are {1}
The followers of 1 are {0}
The followers of 2 are {0,1}
Problem summary: Table: Followers +-------------+------+ | Column Name | Type | +-------------+------+ | user_id | int | | follower_id | int | +-------------+------+ (user_id, follower_id) is the primary key (combination of columns with unique values) for this table. This table contains the IDs of a user and a follower in a social media app where the follower follows the user. Write a solution that will, for each user, return the number of followers. Return the result table ordered by user_id in ascending order. The result format is in the following example.
Start with the most direct exhaustive search. That gives a correctness anchor before optimizing.
Pattern signal: General problem-solving
{"headers":{"Followers":["user_id","follower_id"]},"rows":{"Followers":[["0","1"],["1","0"],["2","0"],["2","1"]]}}Source-backed implementations are provided below for direct study and interview prep.
// Accepted solution for LeetCode #1729: Find Followers Count
// Auto-generated Java example from rust.
class Solution {
public void exampleSolution() {
}
}
// Reference (rust):
// // Accepted solution for LeetCode #1729: Find Followers Count
// pub fn sql_example() -> &'static str {
// r#"
// -- Accepted solution for LeetCode #1729: Find Followers Count
// # Write your MySQL query statement below
// SELECT user_id, COUNT(1) AS followers_count
// FROM Followers
// GROUP BY 1
// ORDER BY 1;
// "#
// }
// Accepted solution for LeetCode #1729: Find Followers Count
// Auto-generated Go example from rust.
func exampleSolution() {
}
// Reference (rust):
// // Accepted solution for LeetCode #1729: Find Followers Count
// pub fn sql_example() -> &'static str {
// r#"
// -- Accepted solution for LeetCode #1729: Find Followers Count
// # Write your MySQL query statement below
// SELECT user_id, COUNT(1) AS followers_count
// FROM Followers
// GROUP BY 1
// ORDER BY 1;
// "#
// }
# Accepted solution for LeetCode #1729: Find Followers Count
# Auto-generated Python example from rust.
def example_solution() -> None:
return
# Reference (rust):
# // Accepted solution for LeetCode #1729: Find Followers Count
# pub fn sql_example() -> &'static str {
# r#"
# -- Accepted solution for LeetCode #1729: Find Followers Count
# # Write your MySQL query statement below
# SELECT user_id, COUNT(1) AS followers_count
# FROM Followers
# GROUP BY 1
# ORDER BY 1;
# "#
# }
// Accepted solution for LeetCode #1729: Find Followers Count
pub fn sql_example() -> &'static str {
r#"
-- Accepted solution for LeetCode #1729: Find Followers Count
# Write your MySQL query statement below
SELECT user_id, COUNT(1) AS followers_count
FROM Followers
GROUP BY 1
ORDER BY 1;
"#
}
// Accepted solution for LeetCode #1729: Find Followers Count
// Auto-generated TypeScript example from rust.
function exampleSolution(): void {
}
// Reference (rust):
// // Accepted solution for LeetCode #1729: Find Followers Count
// pub fn sql_example() -> &'static str {
// r#"
// -- Accepted solution for LeetCode #1729: Find Followers Count
// # Write your MySQL query statement below
// SELECT user_id, COUNT(1) AS followers_count
// FROM Followers
// GROUP BY 1
// ORDER BY 1;
// "#
// }
Use this to step through a reusable interview workflow for this problem.
Two nested loops check every pair or subarray. The outer loop fixes a starting point, the inner loop extends or searches. For n elements this gives up to n²/2 operations. No extra space, but the quadratic time is prohibitive for large inputs.
Most array problems have an O(n²) brute force (nested loops) and an O(n) optimal (single pass with clever state tracking). The key is identifying what information to maintain as you scan: a running max, a prefix sum, a hash map of seen values, or two pointers.
Review these before coding to avoid predictable interview regressions.
Wrong move: Loop endpoints miss first/last candidate.
Usually fails on: Fails on minimal arrays and exact-boundary answers.
Fix: Re-derive loops from inclusive/exclusive ranges before coding.