Off-by-one on range boundaries
Wrong move: Loop endpoints miss first/last candidate.
Usually fails on: Fails on minimal arrays and exact-boundary answers.
Fix: Re-derive loops from inclusive/exclusive ranges before coding.
Move from brute-force thinking to an efficient approach using core interview patterns strategy.
Given a text file file.txt, transpose its content.
You may assume that each row has the same number of columns, and each field is separated by the ' ' character.
Example:
If file.txt has the following content:
name age alice 21 ryan 30
Output the following:
name alice ryan age 21 30
Problem summary: Given a text file file.txt, transpose its content. You may assume that each row has the same number of columns, and each field is separated by the ' ' character.
Start with the most direct exhaustive search. That gives a correctness anchor before optimizing.
Pattern signal: General problem-solving
a
Source-backed implementations are provided below for direct study and interview prep.
// Accepted solution for LeetCode #194: Transpose File
// Auto-generated Java example from rust.
class Solution {
public void exampleSolution() {
}
}
// Reference (rust):
// // Accepted solution for LeetCode #194: Transpose File
// pub fn shell_example() -> &'static str {
// r#"
// # Accepted solution for LeetCode #194: Transpose File
// # Read from the file file.txt and print its transposed content to stdout.
// awk '
// {
// for (i=1; i<=NF; i++) {
// if(NR == 1) {
// res[i] = re$i
// } else {
// res[i] = res[i]" "$i
// }
// }
// }END {
// for (i=1;i<=NF;i++) {
// print res[i]
// }
// }
// ' file.txt
// "#
// }
// Accepted solution for LeetCode #194: Transpose File
// Auto-generated Go example from rust.
func exampleSolution() {
}
// Reference (rust):
// // Accepted solution for LeetCode #194: Transpose File
// pub fn shell_example() -> &'static str {
// r#"
// # Accepted solution for LeetCode #194: Transpose File
// # Read from the file file.txt and print its transposed content to stdout.
// awk '
// {
// for (i=1; i<=NF; i++) {
// if(NR == 1) {
// res[i] = re$i
// } else {
// res[i] = res[i]" "$i
// }
// }
// }END {
// for (i=1;i<=NF;i++) {
// print res[i]
// }
// }
// ' file.txt
// "#
// }
# Accepted solution for LeetCode #194: Transpose File
# Auto-generated Python example from rust.
def example_solution() -> None:
return
# Reference (rust):
# // Accepted solution for LeetCode #194: Transpose File
# pub fn shell_example() -> &'static str {
# r#"
# # Accepted solution for LeetCode #194: Transpose File
# # Read from the file file.txt and print its transposed content to stdout.
# awk '
# {
# for (i=1; i<=NF; i++) {
# if(NR == 1) {
# res[i] = re$i
# } else {
# res[i] = res[i]" "$i
# }
# }
# }END {
# for (i=1;i<=NF;i++) {
# print res[i]
# }
# }
# ' file.txt
# "#
# }
// Accepted solution for LeetCode #194: Transpose File
pub fn shell_example() -> &'static str {
r#"
# Accepted solution for LeetCode #194: Transpose File
# Read from the file file.txt and print its transposed content to stdout.
awk '
{
for (i=1; i<=NF; i++) {
if(NR == 1) {
res[i] = re$i
} else {
res[i] = res[i]" "$i
}
}
}END {
for (i=1;i<=NF;i++) {
print res[i]
}
}
' file.txt
"#
}
// Accepted solution for LeetCode #194: Transpose File
// Auto-generated TypeScript example from rust.
function exampleSolution(): void {
}
// Reference (rust):
// // Accepted solution for LeetCode #194: Transpose File
// pub fn shell_example() -> &'static str {
// r#"
// # Accepted solution for LeetCode #194: Transpose File
// # Read from the file file.txt and print its transposed content to stdout.
// awk '
// {
// for (i=1; i<=NF; i++) {
// if(NR == 1) {
// res[i] = re$i
// } else {
// res[i] = res[i]" "$i
// }
// }
// }END {
// for (i=1;i<=NF;i++) {
// print res[i]
// }
// }
// ' file.txt
// "#
// }
Use this to step through a reusable interview workflow for this problem.
Two nested loops check every pair or subarray. The outer loop fixes a starting point, the inner loop extends or searches. For n elements this gives up to n²/2 operations. No extra space, but the quadratic time is prohibitive for large inputs.
Most array problems have an O(n²) brute force (nested loops) and an O(n) optimal (single pass with clever state tracking). The key is identifying what information to maintain as you scan: a running max, a prefix sum, a hash map of seen values, or two pointers.
Review these before coding to avoid predictable interview regressions.
Wrong move: Loop endpoints miss first/last candidate.
Usually fails on: Fails on minimal arrays and exact-boundary answers.
Fix: Re-derive loops from inclusive/exclusive ranges before coding.