Off-by-one on range boundaries
Wrong move: Loop endpoints miss first/last candidate.
Usually fails on: Fails on minimal arrays and exact-boundary answers.
Fix: Re-derive loops from inclusive/exclusive ranges before coding.
Build confidence with an intuition-first walkthrough focused on core interview patterns fundamentals.
DataFrame: employees
+-------------+--------+
| Column Name | Type |
+-------------+--------+
| employee_id | int |
| name | object |
| department | object |
| salary | int |
+-------------+--------+
Write a solution to display the first 3 rows of this DataFrame.
Example 1:
Input: DataFrame employees +-------------+-----------+-----------------------+--------+ | employee_id | name | department | salary | +-------------+-----------+-----------------------+--------+ | 3 | Bob | Operations | 48675 | | 90 | Alice | Sales | 11096 | | 9 | Tatiana | Engineering | 33805 | | 60 | Annabelle | InformationTechnology | 37678 | | 49 | Jonathan | HumanResources | 23793 | | 43 | Khaled | Administration | 40454 | +-------------+-----------+-----------------------+--------+ Output: +-------------+---------+-------------+--------+ | employee_id | name | department | salary | +-------------+---------+-------------+--------+ | 3 | Bob | Operations | 48675 | | 90 | Alice | Sales | 11096 | | 9 | Tatiana | Engineering | 33805 | +-------------+---------+-------------+--------+ Explanation: Only the first 3 rows are displayed.
Problem summary: DataFrame: employees +-------------+--------+ | Column Name | Type | +-------------+--------+ | employee_id | int | | name | object | | department | object | | salary | int | +-------------+--------+ Write a solution to display the first 3 rows of this DataFrame.
Start with the most direct exhaustive search. That gives a correctness anchor before optimizing.
Pattern signal: General problem-solving
{"headers":{"employees":["employee_id","name","department","salary"]},"rows":{"employees":[[3,"Bob","Operations",48675],[90,"Alice","Sales",11096],[9,"Tatiana","Engineering",33805],[60,"Annabelle","InformationTechnology",37678],[49,"Jonathan","HumanResources",23793],[43,"Khaled","Administration",40454]]}}Source-backed implementations are provided below for direct study and interview prep.
// Accepted solution for LeetCode #2879: Display the First Three Rows
// Auto-generated Java example from py.
class Solution {
public void exampleSolution() {
}
}
// Reference (py):
// # Accepted solution for LeetCode #2879: Display the First Three Rows
// import pandas as pd
//
//
// def selectFirstRows(employees: pd.DataFrame) -> pd.DataFrame:
// return employees.head(3)
// Accepted solution for LeetCode #2879: Display the First Three Rows
// Auto-generated Go example from py.
func exampleSolution() {
}
// Reference (py):
// # Accepted solution for LeetCode #2879: Display the First Three Rows
// import pandas as pd
//
//
// def selectFirstRows(employees: pd.DataFrame) -> pd.DataFrame:
// return employees.head(3)
# Accepted solution for LeetCode #2879: Display the First Three Rows
import pandas as pd
def selectFirstRows(employees: pd.DataFrame) -> pd.DataFrame:
return employees.head(3)
// Accepted solution for LeetCode #2879: Display the First Three Rows
// Rust example auto-generated from py reference.
// Replace the signature and local types with the exact LeetCode harness for this problem.
impl Solution {
pub fn rust_example() {
// Port the logic from the reference block below.
}
}
// Reference (py):
// # Accepted solution for LeetCode #2879: Display the First Three Rows
// import pandas as pd
//
//
// def selectFirstRows(employees: pd.DataFrame) -> pd.DataFrame:
// return employees.head(3)
// Accepted solution for LeetCode #2879: Display the First Three Rows
// Auto-generated TypeScript example from py.
function exampleSolution(): void {
}
// Reference (py):
// # Accepted solution for LeetCode #2879: Display the First Three Rows
// import pandas as pd
//
//
// def selectFirstRows(employees: pd.DataFrame) -> pd.DataFrame:
// return employees.head(3)
Use this to step through a reusable interview workflow for this problem.
Two nested loops check every pair or subarray. The outer loop fixes a starting point, the inner loop extends or searches. For n elements this gives up to n²/2 operations. No extra space, but the quadratic time is prohibitive for large inputs.
Most array problems have an O(n²) brute force (nested loops) and an O(n) optimal (single pass with clever state tracking). The key is identifying what information to maintain as you scan: a running max, a prefix sum, a hash map of seen values, or two pointers.
Review these before coding to avoid predictable interview regressions.
Wrong move: Loop endpoints miss first/last candidate.
Usually fails on: Fails on minimal arrays and exact-boundary answers.
Fix: Re-derive loops from inclusive/exclusive ranges before coding.