Most Frequent Subtree Sum

// Accepted solution for LeetCode #508: Most Frequent Subtree Sum
/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    private Map<Integer, Integer> cnt = new HashMap<>();
    private int mx;

    public int[] findFrequentTreeSum(TreeNode root) {
        dfs(root);
        List<Integer> ans = new ArrayList<>();
        for (var e : cnt.entrySet()) {
            if (e.getValue() == mx) {
                ans.add(e.getKey());
            }
        }
        return ans.stream().mapToInt(i -> i).toArray();
    }

    private int dfs(TreeNode root) {
        if (root == null) {
            return 0;
        }
        int s = root.val + dfs(root.left) + dfs(root.right);
        mx = Math.max(mx, cnt.merge(s, 1, Integer::sum));
        return s;
    }
}

// Accepted solution for LeetCode #508: Most Frequent Subtree Sum
/**
 * Definition for a binary tree node.
 * type TreeNode struct {
 *     Val int
 *     Left *TreeNode
 *     Right *TreeNode
 * }
 */
func findFrequentTreeSum(root *TreeNode) (ans []int) {
	cnt := map[int]int{}
	var mx int
	var dfs func(*TreeNode) int
	dfs = func(root *TreeNode) int {
		if root == nil {
			return 0
		}
		s := root.Val + dfs(root.Left) + dfs(root.Right)
		cnt[s]++
		mx = max(mx, cnt[s])
		return s
	}
	dfs(root)
	for k, v := range cnt {
		if v == mx {
			ans = append(ans, k)
		}
	}
	return
}

# Accepted solution for LeetCode #508: Most Frequent Subtree Sum
# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def findFrequentTreeSum(self, root: Optional[TreeNode]) -> List[int]:
        def dfs(root: Optional[TreeNode]) -> int:
            if root is None:
                return 0
            l, r = dfs(root.left), dfs(root.right)
            s = l + r + root.val
            cnt[s] += 1
            return s

        cnt = Counter()
        dfs(root)
        mx = max(cnt.values())
        return [k for k, v in cnt.items() if v == mx]

// Accepted solution for LeetCode #508: Most Frequent Subtree Sum
// Definition for a binary tree node.
// #[derive(Debug, PartialEq, Eq)]
// pub struct TreeNode {
//   pub val: i32,
//   pub left: Option<Rc<RefCell<TreeNode>>>,
//   pub right: Option<Rc<RefCell<TreeNode>>>,
// }
//
// impl TreeNode {
//   #[inline]
//   pub fn new(val: i32) -> Self {
//     TreeNode {
//       val,
//       left: None,
//       right: None
//     }
//   }
// }
use std::cell::RefCell;
use std::collections::HashMap;
use std::rc::Rc;

impl Solution {
    pub fn find_frequent_tree_sum(root: Option<Rc<RefCell<TreeNode>>>) -> Vec<i32> {
        fn dfs(root: Option<Rc<RefCell<TreeNode>>>, cnt: &mut HashMap<i32, i32>) -> i32 {
            if let Some(node) = root {
                let l = dfs(node.borrow().left.clone(), cnt);
                let r = dfs(node.borrow().right.clone(), cnt);
                let s = l + r + node.borrow().val;
                *cnt.entry(s).or_insert(0) += 1;
                s
            } else {
                0
            }
        }

        let mut cnt = HashMap::new();
        dfs(root, &mut cnt);

        let mx = cnt.values().cloned().max().unwrap_or(0);
        cnt.into_iter()
            .filter(|&(_, v)| v == mx)
            .map(|(k, _)| k)
            .collect()
    }
}

// Accepted solution for LeetCode #508: Most Frequent Subtree Sum
/**
 * Definition for a binary tree node.
 * class TreeNode {
 *     val: number
 *     left: TreeNode | null
 *     right: TreeNode | null
 *     constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {
 *         this.val = (val===undefined ? 0 : val)
 *         this.left = (left===undefined ? null : left)
 *         this.right = (right===undefined ? null : right)
 *     }
 * }
 */

function findFrequentTreeSum(root: TreeNode | null): number[] {
    const cnt = new Map<number, number>();
    let mx = 0;
    const dfs = (root: TreeNode | null): number => {
        if (!root) {
            return 0;
        }
        const { val, left, right } = root;
        const s = val + dfs(left) + dfs(right);
        cnt.set(s, (cnt.get(s) ?? 0) + 1);
        mx = Math.max(mx, cnt.get(s)!);
        return s;
    };
    dfs(root);
    return Array.from(cnt.entries())
        .filter(([_, c]) => c === mx)
        .map(([s, _]) => s);
}